Hello,
Your expected rank will be around 2084.The formula to calculate your expected rank is (100-total percentile)*112679/100
Where 112679 is the total number of candidates appeared for JEE main January session paper 2.
So it is given as (100-98.15)*112679/100=2084.
So this will be your overall rank.You haven't mentioned your category but still you have good chances of getting a college through open category.
You may get seat in following colleges consider 2019 cut off trends

• Malviya National institute of technology, Jaipur
• Maulana Azad Institute of Technology, Bhopal
• NIT, Hamirpur
• NIT, Patna
• NIT, Raipur
• NIT, Rourkela
• NIT, Trichy
• Visvesvaraya National Institute of Technology, Nagpur

But cut off changes every year it may increase or decrease slightly.
You can go through the link for 2019 college-wise cut off
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

You can predict the colleges using our JEE main college predictor

Hello aspirant. Congratulations on your score.
Colleges and cut off can be predicted by rank.
Rank can be calculated like this
(100- your total score)*112679/100
Where 100 is your total percentile score is the percentage of people ahead of you
112679 are the number of candidates appeared for january exam. So through this your rank can be known.
Here I will also post links for rank prediction and all college prediction.
Rank prediction link
https://engineering.careers360.com/jee-main-architecture-rank-predictor
College predictor link
https://engineering.careers360.com/jee-main-architecture-college-predictor
Careers 360 wishes you all the best

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