i got 99.22 percentile in jee 2020 paper 2 in architecture. may i can get spa bhopal

Hi dear,

You have scored 99.22 percentile in JEE main paper 2 that means your rank should be around 878. You can also calculate your rank as

Rank=(100-your percentile)×112679÷100

Last year cutoff of spa Bhopal was around 808. You can check here

https://www.google.co.in/url?q=https://www.careers360.com/colleges/thakur-college-of-engineering-and-technology-mumbai/cut-off&sa=U&ved=2ahUKEwjilvGQ56XnAhUS63MBHUOYBjkQFjAEegQIBxAB&usg=AOvVaw17FFO0-OfebnAr6UMCpMUX

Hope it helps.

Hii

Last year the closing rank at SPA bhopal was 809. It is expected that it will be in same range this year too.

Your jee rank can be calculated using this formula-

(100-percentile)* number of students appeared/100

That crossponds to be in range 880-1170

So, it seems you have low chance on this percentile.  So, perform better in april .

Hope it helps