Hi

In csab crl is considered.

Your profile suggests that your home state is Telangana

It's quite difficult to predict because cutoff keeps changing every year depending upon various factors like :-

******number of students that appeared in the  jee main exam,

****** number of available seats,

****** performance of different students in the examination,

****** the category you belong etc.

But yes,

When we go through previous year trend then

>>>>> With 291222 crl rank

You have low chance in NIT Rourkela for civil engineering even in csab

For example,

In 2020, 2nd round csab, 25346 crl rank was closing rank for OBC category for civil engineering in NIT Rourkela under other state.

You can check the same at

Csab 2020 :- https://admissions.nic.in/csabspl/csabsplresult/result/CurrentORCR.aspx

You have chances in  some of the government engineering colleges which are listed below along with the link for their previous year cut off  :-

• -------) Jiwaji University, Gwalior:- https://www.careers360.com/university/jiwaji-university-gwalior/cut-off

• --------) Dr APJ Abdul Kalam UIT Rajiv Gandhi Proudyogiki Vishwavidyalaya, Jhabua :- https://www.careers360.com/colleges/dr-apj-abdul-kalam-uit-rajiv-gandhi-proudyogiki-vishwavidyalaya-jhabua/cut-off

• -------) Indira Gandhi Engineering College, Sagar :- https://www.careers360.com/colleges/indira-gandhi-engineering-college-sagar/cut-off

This prediction is on the past year data basis but  cut closing rank for colleges changes every year depending upon factors like number of candidates that write jee main examination, difficulty level of the question paper for different shifts of jee main etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Thank you