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Based on the information provided, you have secured 67% in your board examinations and a score of 49.9 in JEE Mains. Chitkara University, Punjab, requires candidates to have passed their 10+2 examination with a minimum aggregate of 60% or at least 60% in Physics, Chemistry, and Mathematics. Additionally, appearing for JEE Mains is mandatory for admission to the B.E. in Computer Science Engineering (CSE) programl.
While you meet the eligibility criteria, admission to the CSE program is competitive and based on merit. Specific cutoff scores for JEE Mains are not publicly disclosed by the university. Given your JEE Mains score of 49.9, it is advisable to contact Chitkara University's admissions office directly to assess your chances of securing a seat in the CSE program.
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