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I am OBC category telangana
B.Tech/B.Arch Admissions OPEN
Hello Pavansai
Congrats for 95.3975 percentile in JEE mains 2019
There is a pedicted formula from our team to predict rank
Total No of students = 874469
formula
Probable Rank= ( 100 - NTA percentile ) x 874469 / 100
So your predicted rank = 40247
We are not sure that you will get NIT warangal or not but you can check previous year cutt off and than tally your rank with that .
Please visit our website for previous year NIT warangal Cutt Off
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-warangal
I hope you get My point.
Thank You and GOOD LUCK!!!
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