I have got 1731 rank(OBC) in JEE Advanced 2019 and 2000 rank(OBC) in JEE Mains 2019. What should I choose: IIT KGP(Industrial) or NITR(CSE)?

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I have got 1731 rank(OBC) in JEE Advanced 2019 and 2000 rank(OBC) in JEE Mains 2019. What should I choose: IIT KGP(Industrial) or NITR(CSE)?

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Ankit Kumar Sahoo 9th May, 2019

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Prashant Gandhi 18th Jun, 2019

Hi Ankit,

So glad that you really cracked both of them fortunately. I would always advise to choose a branch over a college. Please pursue your interests. Sometimes we are blinded by the brand name,and it's okay. Choose one that you like doing,Computer Science or Industrial Engineering. It is completely okay to go with NITR over IIT KGP. Think carefully.

Good Luck!

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ka517 Student Expert 18th Jun, 2019

Hello Ankit,
Choosing a branch is completely upto you. If you are interested in Computer science engineering choose it. If you are interested in the other one choose that. If you want to choose a branch based on the packages you get right after college, then,
IIT kgp industrial design - 30-40LPA
NITR CSE - 39LPA(highest), 3LPA(lowest)
Choose wisely by considering factors like your interests and the academic areas you are good at.

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Ankit Kumar Sahoo

20th Jun, 2019

30-40LPA is the average placement of industrial engineering in IIT Kharagpur?

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ka517

Student Expert 20th Jun, 2019

No, it is the highest package.

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