Hello,

In 2019 the cut off for NIT, Calicut for B.Arch was 693 for OBC category(home state). If we calculate your expected rank based on the percentile you score your rank will be around 10479.You expected rank can be calculated by the formula (100-your total percentile)*112679/100

In January session 112679 candidates appeared in JEE main paper 2.

Now, your rank based on category will be around 1000 considering previous year cut you have very few chances of getting seat in NIT, Calicut but cut off may increase or decrease depending on number of candidates appeared, number of seats available, difficulty of exam etc.

You may try our JEE main college predictor to know the colleges in which you may get seat

Hello,

In 2019 the cut off for NIT, Calicut for B.Arch was 693 for OBC category(home state). If we calculate your expected rank based on the percentile you score your rank will be around 10479.You expected rank can be calculated by the formula (100-your total percentile)*112679/100

In January session 112679 candidates appeared in JEE main paper 2.

Now, your rank based on category will be around 1000 considering previous year cut you have very few chances of getting seat in NIT, Calicut but cut off may increase or decrease depending on number of candidates appeared, number of seats available, difficulty of exam etc.

You may try our JEE main college predictor to know the colleges in which you may get seat