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I scored 97.3 percentile in jee paper 2. I'm from obc category. I wish to study arch in SPA delhi . Will my score be sufficient?


revathi s 14th Dec, 2019
Answers (2)
Pachigolla Hemanth 23rd Jan, 2020

Hello Revathi,

The official rank list will be released by NTA after the completion of the April session of the exam.

The predicted rank by using the formula:.

(100-your percentile)*no.of students wrote the exam/100.

for the january exam total no of students are 112679

then your rank is 3042. Referring to the previous year cutoff trends of SPA, the chances of getting admission with this ranking is quite slim. Your ward could try to improve their performance in the April session of the exam.For more details once visit the below link

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

B.Tech/B.Arch Admissions OPEN

Apply to Amity University-Noida B.Tech Admissions 2026

Hope this helps you...

Shubham Dhane 23rd Jan, 2020

Hello,

We can use the below formula to calculate your approximated rank

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

Your expected rank will be around 3042.

But the last year cut off was 733 for OBC. So you may not get into SPA delhi

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