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minimum percentile required in jee mains for cs in mnit allahabad


abhay dubey 5th Jan, 2019
Answers (3)
Shiv Kumar Gupta 14th Feb, 2019
Hello Abhay,
For MNIT Allahabad, cut off of CSE is about to 4k for general home state quota. If you belong to other state then you have to score rank under 2k for CSE.
here is the rank predicter according to the percentile. Click the link and predict expected rank
https://engineering.careers360.com/jee-main-rank-predictor?icn=JEE_Main_rp&ici=JEE_Main_article_contmap
And according to the rank, previous year cut off trends of this college here
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-mnnit-allahabad/amp
Thank you.
Maligaveli sai pavan 14th Feb, 2019
Hello Aspirant
.
For all categories as per previous years trends you should get around 5000 below rank. For general it opening rank is 1617 and 4373. For OBC NCL oc ( opening rank) is 891 and closing rank is 1666.for sc the opening rank is 646 and closing rank is 911. For st category the opening rank is 181 and closing rank is 365 . This is as per previous years cutoff. As per now results only percentile score is released you have to wait for official results which were released after the second jEE mains april exam is conducted.
.
If you want to know previous years cutoff once visit this below link:-
.
.
Thank you!!!
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ROHIT K 14th Feb, 2019
Hello
The minimum percentile or marks will vary from category to category and also competition as well so please mention the category of your so that we can predict the approximated percentile but this year the JEE mains is conducting twice so we should wait till April session exam have to completed

Good luck

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