Hey there

Cutoff for OBC NCL in jee mains 2020 is 72.8887969. this is the cutoff which should be a minimum percentile acheived by a candidate for JEE advanced exam.

check the link

https://engineering.careers360.com/articles/jee-main-cutoff

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

good luck

Hello student,

Congratulations on your result.According to NTA, the cutoff for OBC-NCl category is 72.8887969. Since the JEE mains result has been announced, please check your percentile.If your percentile is greater than 72.8887969 , you are eligible to write JEE Advanced

I sugggest you to go through the previous years cut off ranks through the given link

https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits

Feel free to reach out to Careers360 in case you have doubts regarding your career