Latest: Free All-India JEE Main 2026 Mock Test - Attempt Now
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Going by the formula 100-87.22*869010/100 wherein your percentile is 87.22 and 869010 is the no.of Candidates who appeared for JEE Mains, your All India Rank is approximately 111059. In 2019, the Cut off rank for RNS Institute of Technology was around 44000. So with an All India Rank of 111059, you unfortunately cannot get a seat in this College. You may have to appear for July session. Cut offs change every year but this vast difference might not be possible.
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