Hello Aspirant,

There are few factors on which the cut off depends:

• Difficulty level
• Number of applicants
• Performance
• cut-off trends

JEE MAIN cut-off for 2020 (OBC NCL)

• Computer Science & engineering-

Home state male-5596                       Home state Female-7782

Other state male-2616                       Other state Female-4822

• Electronics and communication engineering

Home state male-8480                       Home state female-13065

Other state male-4636                       Other state female-9524

• Electrical and electronics engineering

Home state Male-11491                     Home state female-15296

Other state Male-6035                       Other state female-11590

For the year 2019

• Computer Science & engineering-

Home state male-5938                       Home state female-12880

Other state male-2429                        Other state female-6003

• Electronics and communication engineering

Home state male-10104                  Home state female-16879

Other state male- 4208                     Other state female-7169

• Electrical and electronics engineering

Home state male-11818                       Home state female-17667

Other state male- 5319                                  Other state female-9804

It is not possible to detect the marks as the admissions are based on All India Ranks and not Marks. So I suggest you to take a look at the previous year cut-off ranks and analyze yourself.

You can further check out the ranks on : https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-delhi

Hope this information helps you

All the best

In the JEE of year 2020, the the maximum marks for NIT Delhi cutoff score for OBC candidates are 73 whereas the minimum score required for NIT Delhi cut off are 45. However in the case of SC/ST categories, the maximum and the minimum marks 73 and 29/24 respectively.