Dear Applicant though you cannot predict a certain rank but can just make an assumption because based on the number of applicants and the difficulty level of the exam the cut off is determined. The genuine rank that you need to secure as an OBC candidate being from home state, is around 3000-3500 to get admission into Computer Science Engineering course. Go through the cut off trend

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra

Good luck!!

Hello Aspirant

NIT Kurukshetra has good faculty members, infrastructure, very good placement statistics every year. Placements in the academic year of 2019-2020 were pretty good, more than 76% of the students got placed, which is comparatively less due to COVID situation in the country.

To secure a seat in Computer Engineering in NIT Kurukshetra through JEE Mains you would have to score at least 99.6-99.7 percentile based upon the cutoff of previous years.

If you want the precise opening and closing rank for NIT Kurukshetra CSE, go through the link given below:

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra

Hope this helps