Hello!!!

Hope you are doing great!!!

As per your question,the chemical equation will be as follows:

2Al+2NaoH+2H2O   gives rise to  2NaAlO2+3H2

2*27gms of Al         =              6gms of H2

0.15gms of Al          =              ?

weight of H2 produced = 0.15*6/2*27

= 1/60 gms of H2

By using Ideal gas equation,

PV=nRT

where P=pressure

V=volume

R=universal gas constant=0.8314

T=temperature in kelvin

PV=nRT

1*V=(1/60*2)*(0.8314*293)

V=(1/120)*(23.44)

V=23.44/120

V=0.195lit

Hope it helps!!!!!!