New: JEE Main 2026 Answer Key Out; Download Now
JEE Main 2026 Tools: Rank Predictor | College Predictor
JEE Main 2026: Session 2 Registration Link | Session 1 Official QP
Comprehensive Guide: IIT's | NIT's | IIIT's
Hi Sravankumar,
SASTRA University does not have any cutoff rather it calculates your eligibility using the following formula- (12th percentage x 0.75) + (JEE Main Percentile x 0.25). It takes into account the JEE Main normalised scores as well as the 10+2 marks and calls for admissions under 2 streams -
Stream 1:- JEE Main 2018 and normalized 10+2 scores will be taken together for admission under stream 1- The JEE Main scores will carry 25% weightage and 10+2 scores will carry 75% weightage.- The combined scores will be used to prepare the rank list and candidates will be invited for admission on the basis of the rank list.- 70% of seats will be filled under stream 1.
Stream 2:
- Candidates will be considered for admission based on their normalised aggregate 10+2 or any equivalent exam scores.- 30% of seats will be filled under stream 2.
Now having explained the process, I advise you to kindly wait till any announcemets are made by the University and I hope that with that brilliant result, you get an admission in SASTRA.
All the very best! I hope this was useful.
Use the JEE Main 2026 Rank Predictor to estimate your expected rank based on your scores or percentile and plan your college options smartly.
Answer Key | Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile