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How much marks out of 300 are required for getting CSE in DTU if I am from Delhi and my category is General
Answer (1)
Hello,
In 2019 the All India cut off rank for admission to Computer Science Engineering in DTU for general category was 5896 in round 1 and the cut off in round 4 was 8852 under Delhi region. You need to score minimum 99 percentile and score minimum 180-200 marks in JEE Main to have decent chances of getting seat. CUt off may increase or decrease depending on number of candidates applied, difficulty of exam, number of seats available etc.
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