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I am an OBC student from Andhra Pradesh. I am expecting 165/300 marks in JEE Mains September 2020. Can I get CSE branch in NIT KURUKSHETRA HARYANA?


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paidikalayesukrishna 28th Jul, 2020
Answers (2)

Hi aspirant,

You are getting 165 marks in JEE Main and belong to OBC category. Based on this mark your percentile would be 98.5 approximately. You can see the previous year rank vs marks analysis here:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-marks-vs-percentile/amp

Based on this percentile your Common Rank list (CRL) rank would be 16,000 approximately and the corresponding OBC category rank would be 3,500 approximately. The last year seventh round closing rank for OBC category for Computer Science Engineering (CSE) was 2,839 under home state quota and 2280 under other state quota. Your rank is more than that but chances are as it is approximation. Nevertheless, you can see your other options by using our college predictor tool

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2026

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor

piyushgupta15ptps 6th Sep, 2020
Hi there , As your score is 164 out of 300 then you must have percentile in between 98.8765456 to 99.2334155. Thus your Rank will lie in below 11000. And you can use the link below to know the cutoff of CSE branch in NIT kurukshetr.
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra
Good luck for future.
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