JEE Main 2026: Preparation Tips & Study Plan
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Dinesh in order to get admission in Sastra there is no fixed cut-off. It is totally based on the 12th class percentage and Jee main marks. Your aggregate marks will be calculated with this formula: 12th percentage * 0.75+jee main mark * 0.25. Maximum marks which you can get is 165. Now on the basis of this aggregate marks a merit list will be prepared for all the students who are applying to pursue B.Tech degree from Sastra university and on the basis of your merit rank plus your stream priority you will be allotted the branch. Again there is no fixed cut-off for any branch but in order to get admission in the most demanding computer science branch according to past records your rank needs to be atleast in top 500.
Feel free to ask if you have any more queries. All the best!!
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