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What is the minimum rank of jee advanced for join to aerospace engineering in IIT kharagpur?


bharathkumars5204 18th Feb, 2019
Answers (3)
Arnab Ghosh 30th Mar, 2019
Hi Bharat,

IIT KGP is known for its academic & mind-blowing placement record over years.

Aerospace Engineering (JEE ADVANCED) cut off:



General :OR-2408 & CR-3464

OBC-NCL : OR-1214 & CR-1685

Sc: OR:255 & CR:655

ST: OR:331 & CR:354

All the best for you preparation.







4 Comments
Comments (4)
30th Mar, 2019
I can't understand symbols OR and CR
Reply
30th Mar, 2019
OR= Opening Rank
CR= closing rank
Reply
30th Mar, 2019
Ho
Thank you
Reply
5th Aug, 2021
opening rank and closing rank means sir please?
Reply
Ritika Rani 30th Mar, 2019

Hi

This is Ritika

The cutoff of any branch of IIT  college depends on the exam of jee advance and the level of difficulty of the questions.

The cutoff basically depends on the results of jee advance,but as a idea you can see the cutoff of jee advance of last year for this do visit on https://www.google.co.in/amp/s/engineering.careers360.com/articles/iits-cutoff-for-b-tech-aerospace-engineering/amp

For any further enquiry please do comment

Hope I will be able to help you

Thank you

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Santwana J Singh Student Expert 30th Mar, 2019

Hello Bharath!

The closing rank for Aerospace Engineering in IIT KHARAGPUR was 3464 last year in JEE ADVANCED. It was for General Category applicants. Just don't prepare for JEE ADVANCED with this Rank aim in your mind. Try to achive the highest you can and then you may land around this rank. Just don't aim this rank, aim higher.

All the best!

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