how much rank is needed in JEE advanced to get into IIT Kharagpur ,Kanpur, Roorkee ,Goa ,Hyderabad with mechanical engineering and aerospace engineering dual degrees ....
Hello,
The closing ranks for various courses varies every year.According to JEE Advanced 2019 the closing ranks for Mechanical Engg for various categories are given below :
IIT Kharagpur :
General - 2259
OBC - 921
EWS - 178
SC - 453
ST - 268
IIT Kanpur :
General - 2108
OBC - 890
EWS - 181
SC - 576
ST - 342
IIT Roorkee :
General - 2748
OBC - 1084
EWS - 231
SC - 654
ST - 329
IIT Hyderabad :
General - 3609
OBC - 1260
EWS - 298
SC - 840
ST - 390
IIT Goa :
General - 9473
OBC - 3605
EWS - 1052
SC - 1583
ST - 710
The closing ranks for Aerospace Engg for various catogories are given below :
IIT Kharagpur :
General - 3822
OBC - 1651
EWS - 398
SC - 1079
ST - 590
IIT Kanpur :
General - 3497
OBC - 1717
EWS - 357
SC - 1084
ST - 608
Visit the links below for more details regarding the closing ranks :
https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-mechanical-engineering
https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-aerospace-engineering
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