Hello,

In 2019 a candidate with 68 rank belonging to ST category secured seat in IIT, Roorkee in Computer Science Engineering. It is difficult to predict the marks because JEE Advanced marks are not same every year. The total maximum marks changes every year. And your rank depends on number of candidates belonging to your branch, top score etc. A safe score is in between 40%-50% of total marks. In 2019 the total maximum marks were 372 according to this 40-50% means 148-186 marks. But this year maximum marks changes. So your aim must be to score 40%-50% of total marks.Cut off changes every year depending on number of candidates appeared, difficulty of exam, number of seats available etc.