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i got 97.3 pecentile in jee main 2020 im obc candidate and karnataka is my home state which branch can i get in nitk surathkal


Ramu pm 20th Dec, 2019
Answers (2)
ARNAV SATRUSAL 29th Jan, 2020

Hi Ramu,

Congrats on scoring 97.3 percentile.According to your percentile, your rank will be around ((100-97.3)*869010)/100 which is around 23k.

Again as the number of students appearing in the April attempt will change, your rank will fluctuate. As per your rank,and considering your category ;you can get Mechanical, Metalurgy,Mining,Chemical,Civil, in spot round considering previous year trends. But, I will advice you to give your best for the April attempt and try to score a better percentile to get into a branch of your choice.

You can go through the following link to predict different colleges for you:

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2026

Wishing you all the very best for your future exams and for your April attempt.

priyaankasarkar Student Expert 29th Jan, 2020

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 23463 . This is your overall Category. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.

Based on previous cut offs for NIT Surathkal at https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal ,this rank is tad higher for a seat in any branch. You may have to appear for April session.

But you might have a shot at:

NIT Warangal

NIT Rourkela

NIT Calicut

MNIT

VNIT, Nagpur

Now to predict colleges, please use our college predictor:


2 Comments
Comments (2)
29th Jan, 2020
How can it increase to 12 lac
Reply
Student Expert 29th Jan, 2020
That is the no.of Candidates expected to appear for April session.
Reply
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