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what is the percentile that i have to get to opt for btech cse course in nit surathkal


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gowseikbablu 7th Apr, 2020
Answer (1)
Devanshi Adhikari 17th May, 2020

Hello aspirant,

To get admission in NIT Surathkal a candidate has to get above 99 percentile to get CSE branch. Below is the 2019 JEE MAIN cut-off for NIT Surathkal for CSE branch:

Course Name

Category

Male

Female

Home State

Other State

Home State

Other State

Computer Science and Engineering

OBC

2627

623

7857

2295

EWS

1102

248

4610

414

General

3561

2156

4920

3874

SC

1011

285

2337

682

ST

336

105

1403

552

For more information you can visit:

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal

Thank you.

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