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I have got 292/300 (phy -100,bio -97,chem-95)in pu board and my cet pcb score is 102/180 (bio -48,phy-26,chem - 28)what will be my approximate bsc ag rank this year


Nikhil Rudra 22nd Jun, 2020
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mjaisinghani62 1st Aug, 2020

Hello aspirant

Cut off marks are calculated by dividing marks secured in each subject by 4 + 50 . Then total marks are divided by number of subjects.

As you have got 48 marks in biology, 48/4 = 12

Your cut off for Biology will be 12+50=62

Physics 26/4=6.5 + 50 = 56.5

For chemistry 28/4 = 7 +50 = 57



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1st Aug, 2020
what will be my approximate ranking
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