Pt Deen Dayal Mahavidyalaya, Ladampura All Questions

The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. NITs cutoff varies to Home state quota & Other state quota, With this rank the chances seems less to get a seat in NITs

Hello Gagandeep N A,

On the basis of the rank only the cutoff for college is decided.We can't predict the college.You can go for college predictor which Colleges are available for your percentile.

You can predict the college by your percentile from the link given below from careers 360 -

Hello karan

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this

Hey daran! Thanks for contacting careers 360.

For candidates to qualify for the admissions to nit's /iit's/ gfti etc they should have secured at least 75% marks in class 12 or be in the top 20 percentile in class 12 exam conducted by the respective boards.

You can refer to

Hey Sandeep.

You can use the formula given below to calculate JEE B.Arch Rank by percentile -   

(100- your total percentile score) * 1,45,386/ 100. 

According to your percentile, on applying this formula you can expect a rank around 10,600.

You can use the link which is given below to

Hello Kanchan. Thank you for choosing Careers360. 

According to the experts for JEE Mains paper 2,  the candidates who have 85 percentile or more have a high chance to qualify.

Also, to know your probable rank, you can use the formulae, (100-percentile) × 1,45,000 /100

Hope this helps!

Hello!Janitha

Your total Percentile is too low.But your percentile in mathematics is good.Rank will be given on the basis of total percentile score.Don't worry you still have one attempt for jee mains 2019.You have plenty of time in it.Focus on three sub(phy,chem and maths) equally.Try to balance among them.Solving 15

The exact prediction would be difficult about the qualifying marks or rank as JEE Main is being conducted twice by NTA for the first time.

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be