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The calculation of the marks would be difficult, You can check JEE Main paper II answer key with the given below link to take an idea about the marks.
https://engineering.careers360.com/articles/jee-main-paper-2-answer-key
A total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100-
Your
It would be difficult to provide you the exact information about the qualifying score or admission cutoff of NITs as JEE Main is being conducted twice by NTA for the first time.
As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386
Hello sakshi
Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this
Hello dewansh
NTA will release the cutoffs in April so right now we can't predict whether you are eligible but as per the past trends and our experts candidates having percentile above 85 are supposed to be qualified for advance.
So please wait till then and hope for the best.
Hello Abhay. Thank you for choosing Careers360.
As we know that there will two JEE Mains Exams this time. However, according to the experts people with 85 percentile or more have very high chances to qualify for the next exam.
You should definitely try for the exam in April as
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