Amity University-Noida B.Com Admissions 2026
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Dear aspirant,
Firstly congratulations for the result you have got. As of know NTA Has not released the official cutoffs so we can't predict whether you will get a NIT seat or not. So please wait till April to know whether you will get a NIT seat or not .but
Firstly congratulations for the result you have got. As of know NTA Has not released the official cutoffs so we can't predict whether you will get a NIT seat or not. So please wait till April to know whether you will get a NIT seat or not .but
Hello Aspirant
.
You may get Nit by previous years cutoff of Colleges but this year the exam held twice and difficult to predict the college you have to wait for official results which were released on the month of April by national testing agency NTA.
.
Use this formula
.
You may get Nit by previous years cutoff of Colleges but this year the exam held twice and difficult to predict the college you have to wait for official results which were released on the month of April by national testing agency NTA.
.
Use this formula
With this rank you can easily get into state level engineering college(both government and private ). To know more about the college that you can get use careers360 college predictor link given below
https://engineering.careers360.com/jee-main-college-predictor
Thank you and have a great future ahead
https://engineering.careers360.com/jee-main-college-predictor
Thank you and have a great future ahead
Hello Abhay. Thank you for choosing Careers360.
As we know that there will two JEE Mains Exams this time. However, according to the experts people with 85 percentile or more have very high chances to qualify for the next exam.
You should definitely try for the exam in April as
Hello Aspirant
.
It is difficult to predict the college since the official cutoff was not yet released by national testing agency NTA.it was released on the month of April after the second jEE mains exam is conducted.
.
Use this formula to predict the rank:
Rank Formula = (100
.
It is difficult to predict the college since the official cutoff was not yet released by national testing agency NTA.it was released on the month of April after the second jEE mains exam is conducted.
.
Use this formula to predict the rank:
Rank Formula = (100
Dear Aspirant,
With a percentile that good, you can expect to get admit in a fairly good NIT and a fairly productive branch. You should visit official websites of following NITs and look forward to get into one of these.
1. NIT Rourkela : http://www.nitrkl.ac.in/
2. VNIT Nagpur : http://vnit.ac.in/
Dear aspirant,
Your rank will be nearly (100-95.6)*145386/100=6396 based on previous year trends.And chances are there with NITs
You have chances with
NIT raipur
NIT Hamirpur
For last year NIT cutoffs go to
Https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp
Good luck
Dear aspirant,
Your rank will be nearly (100-95.6)*145386/100=6396 based on previous year trends.And chances are there with NITs
You have chances with
NIT raipur
NIT Hamirpur
For last year NIT cutoffs go to
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Good luck
Hi,
As 1,45,386 students appeared this year for the examination according to that by using the Rank Formula (100-Total percentile)*145386/100 your rank will be around 16719
This is your approximate rank.
According to your predicted rank you may get NIT Harimpur (Home quota) according to previous year cut offs .
As 1,45,386 students appeared this year for the examination according to that by using the Rank Formula (100-Total percentile)*145386/100 your rank will be around 16719
This is your approximate rank.
According to your predicted rank you may get NIT Harimpur (Home quota) according to previous year cut offs .
Hello Srivatsa
Congrats for 91.86 percentile in JEE mains 2019 paper 2
We can't say that which college you will get but we can predict your rank from the given percentile.
There is a predicted formula from our team to predict rank
Total No of students = 145386
Formula
Probable
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