Amity University-Noida B.Com Admissions 2026
ApplyAmong top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Hello Gautom,
207 must be your marks in JEE mains paper 2.
In order to get your rank you have to tell your percentile.
So please comment your percentile.
For more details you can get refrence from career 360 website :
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
thanks
Dear aspirant,
Your rank will be nearly (100-68.84)*145386/100=45302 based on previous year trends.And chances are less to be qualified to appear for jee advanced exam as experts predicted cutoff to be nearly 85 percentile for general candidate.
Good luck
Hi Vinslin,
This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 1163. Calculating marks using percentile is not
Hi Ishika Soni,
Congratualtions on your succesfull results. This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 382. Calculating
Hello arjun,
Congratulations for your performance
Total number of students appeared for jee main 2 paper id 180000.
So you can calculate your rank by this method:
180000×(100- obtained percentile)/100
By this your rank would be around 34000.
Good luck
Hi,
Your percentile are very less for government college. You can go through the link provided below for more details .
All the best !!
https://engineering.careers360.com/jee-main-college-predictor
https://engineering.careers360.com/articles/jee-main-rank-list
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
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