OUAT Bhubaneswar All Questions

Hello Sanjana,

Your OUAT weightage is calculate as follows:-

(10th / 4 )+ (12th/4)+ (Entrance Mark/4) = Weightage

And the 12th class (Average of PCM or PCB whichever is more, the total mark of 12th is not taken into account , only PCM or PCB).

You have not mentioned your PCB/PCM average in your question. So, it is difficult to calculate your weightage in OUAT. Also, your marks scored in the entrance is really less(the weightage will be only 15). And your 10th weightage is 14.75.

So, the combined weightage of both entrance and 10th(not including 12th) is only 29.75. Looking at your +2 % also, it does not seem like your +2 weightage will be more than 20.

So, if I assume your +2 weightage to be 20, your OUAT weighatge will become 49.75 which is really low. You may not even get BSc agri in OUAT Bhawanipatna, but it is hard to tell as the higher rank holders may not accept the seats. So, you may have very less chances in OUAT Bhawanipatna in the last rounds of councelling. OUAT Bbsr is out of question.

Hope this helps:)

Dear Aspirant,

As you have mentioned you got 67 in OUAT examination as well as you have SC category , I think you will get a government college but some specific one only.

you can go for the following colleges- B.Sc.(Agriculture) Bhawanipatna ,B.Sc.(Horticulture) ,B.Sc. (Agriculture) Chiplima , B.Sc.(Forestry)  , B.Tech(Agricultural Engineering) ,B.Sc.(Home Science) ,B.F.Sc .

good luck!!!

Dear Aspirant,

As you have mentioned you got 67 in OUAT examination as well as you have SC category , I think you will get a government college but some specific one only.

you can go for the following colleges- B.Sc.(Agriculture) Bhawanipatna ,B.Sc.(Horticulture) ,B.Sc. (Agriculture) Chiplima , B.Sc.(Forestry)  , B.Tech(Agricultural Engineering) ,B.Sc.(Home Science) ,B.F.Sc .

good luck!!!

Hello Satyaranjan!

Ouat weightage is calculated as:-

25% of  % scored in HSC/equivalent +25% of % scored in +2 Sc/euivalent + 50%* of ouat ug cee marks.

(*OUAT entrance mark will have half the value of total weightage. So out of total 100 weightage 50 will be from OUAT marks. And as the total mark of OUAT entrance is 200, so u have to divide it by 4 to get 50.)

I.e, it will be the sum of (1/4)th of marks in the above three exams.

For example, if a candidate have secured 58% in HSC/equivalent, 67% in PCB/PCM in +2 Sc/equivalent and 123 out of 200 in the entrance test, his or her weighted score would be 0.25*58 + 0.25*67 + 0.25*123 =62.00.

(Only PCB or PCM marks of +2 Sc is considered depending on the subject discipline you appear in the entrance test)

Hope you understood.

All the best!

Hey!

Odisha University of Agriculture and Technology Entrance Exam (OUAT) is conducted for the admission in various degree Programmes i.e.B. F. Sc, B. V. Sc. & A.H, B. Tech. (Agril. Engg.), B.Sc. (Hons.) Community Science, B.Sc. (Hons.) Horticulture, B.Sc. (Hons.) Forestry, B.Sc.(Hons.) Agriculture.

There is no attempt limit for giving this exam but the eligibility criterias are important so if you qualify those you are religible to give the entrance exam.

You can visit this link for further details.: https://www.google.co.in/amp/s/university.careers360.com/articles/ouat/amp?espv=1

Hello there!

OUAT i.e Odisha University of Agriculture and Technology conducts its own entrance examination and the admissions into various courses are done through the OUAT counselling process.

So, there is no any chance of getting a veterinary seat from this university on the basis of your NEET score.

If you want to know more about the AIPVT counselling which is conducted by VCI (Veterinary Council of India) and accepts NEET score for admissions then, visit this link. https://medicine.careers360.com/articles/aipvt-counselling

For more information on expected colleges you can get on the basis of your NEET score, use this college predictor tool. https://medicine.careers360.com/neet-college-predictor?icn=QnA&ici=qna_answer

All the best!

Hii there,

For OAUT, first when you login with your email ID, phone number and captcha, your account opens. There you can know all details.

The exam for OUAT 2020 is to take place on 11 October, 2020. The application form for PG courses have been extended till 30 sptember, 2020. Till now there is no information on admit card so stay tuned on the official website.

https://www.careers360.com/university/orissa-university-of-agriculture-and-technology-bhubaneswar/amp

https://university.careers360.com/articles/ouat

Good luck!!

Dear Student,

There is no need to worry about your application number. Kindly check your email or check your messaging app wherein you might have received notification while you were filling the form. You can get the application then & there itself. Please write this somewhere else in future so that you don't have to worry about it later.

Thank you for your query.

Hello Rudradev !

OUAT entrance exam 2020 will be held in offline mode.

The questions asked in the UG and PG entrance exam will be of objective type. For admission into PG Programmes the question paper will contain total of 200 MCQs.

For admission into UG Programmes the entrance test will contain questions from the subjects of Physics, Chemistry and Mathematics/Biology. For admission into PG programmes, the entrance test will contain questions from the subjects studied in the Bachelor’s degree.

All the best !