Birla Institute of Applied Sciences, Nainital

Hello Aspirant,

See if your friend got a call from IIM Ahmedabad which is the topmost IIM of India then he/she might be belonging to SC/ST/PwD category and cut-offs for these categories are quite low around 60-70 percentile in CAT and also note that these ar the top Management institutions of India they do not involve themselves in such kind of biasing or an unfair means because it will directly affect their reputation.

For more clarity let us understand the complete admission and shortlisting process of IIM Ahmedabad:-

IIM Ahmedabad

Admission process for IIM A is a two step process. First step is for preliminary screening on the basis of Sectional cut-offs and overall cut-offs along with different rating points for IIM A which are described in the tables below and you need to clear sectional cut-off as well as Overall cut-off :-

Ratings on the basis of class 10th score :-

Rating on the basis of class 12th score :-

Rating scores on the basis of field of graduation and percentage :-

Rating scores on the basis of work experience (if any) :-

After considering all the ratings on the basis of above discussed factors candidates are shortlisted for Step 2 which is Analytical Writing Test and Personal Interview round.

You can check out complete admission process for IIM A from the link given below :-

https://bschool.careers360.com/articles/iim-ahmedabad-admission-criteria

You can check out the link given below for complete admission Process of other IIMs as well :-

https://bschool.careers360.com/articles/iim-admission-criteria

You can also use CAT Pathfinder to predict your chances to get call from different IIMs and non IIMs :-

https://bschool.careers360.com/pathfinder/cat

I hope this information helps you.

Good Luck!!

Hello student,

You have not mentioned the diode type, so we are taking it as a Germanium diode.

Now, Forward Bias Voltage / Vd = 0.25  Volts

Reverse Saturation Current / Is = 1.2 uA

Temperature = 27'C = 300'K

AC Resistance = Rd = Vd/Id

So, first of all, we have to find Id.

Now we know that, Id = Is . ( e^Vd/nVt - 1 )

Hence put the values in this eqn, so we get Id = 0.018 A

now, Rd = 0.25/0.018 = 13.88 ohm

Hope it helps.

Dear student,

We have to find the Reverse Saturation Current i.e. Is.

Now, Forward Bias Voltage/Vd = 0.27 Volts

Temperature = 300'K

Diode Current/Id = 50mA

Now, we will use the current equation.

Id = Is . ( e^Vd/nVt - 1 )

Now put all the values in this given equation, we have

Is = 1.46 microA

Hope it helps.

Hello Candidate,

The given diode is Silicon Diode , hence n = 2. First, we will check all the given things, and after that we will check the things which we have to find.

Now, Diode Current, Id = 10 mA

Reverse Saturation Current, Is = 25 * 10^(-7) A

Temperature = 300'C

Forward Bias Voltage = Vd

We use the formula, Id = Is . ( e^Vd/nVt - 1 )

So now, Put all the given values in the equation, and hence we have get the Vd.

Vd = approx ( 0.18 V )

Hope it helps.

Birla Institute Of applied science is a very good college and definitely you can get a very good seat i.e. computer science at your ranking in JEE Mains.

Generally the cutoff is opening at around 1 lakh for general category, so you can surely expect CSE branch from it.

I hope you will do best in your life and don't take much stress.

My best wishes to you