JIIT Noida All Questions

JIIT appears on the top position for rankings of private universities in the NCR region, and it has better equipment's with good faculty. So if you compare between Amity University and JIIT(noida), JIIT(noida) is the better option for the BTech Computer Science Engineering.

Hi Prakhar,

Yes, you can get admission in CSE in Jaypee, Noida with this percentage. The minimum eligibility criteria for taking the admission is:

• The candidate must have passed 10+2 or its equivalent with minimum of 60% aggregate marks with Physics and Mathematics as compulsory subjects and one out of :- Chemistry, Computer Sciences, Informatic Practices, Multimedia & Web technology, Engineering Drawing, Engineering Graphics & English.
• Candidates' date of birth(as recorded in the High School/Secondary Education Board/University Certificate) must fall on or after October 01, 1999

Hope this helps! All the best!

Dear Student,

This year Jaypee B.Tech admission 2020 will be on the basis of 10+2th level result. The minimum marks for this is 60% marks in Physics, Chemistry or computer science and in mathematics.

Now you have 83% marks, and those students who have scored more than 70% marks in 10+2th level they can get the direct admission in JAYPEE NOIDA.

Visit the official website for admission.

Thank You.

Hello,

You score is quite good at HSC level. So, you are eligible to get admission in Thapar Institute of Engineering & Technology. You also have to score good in JEE Mains. The eligibility criteria for 2020 is:

1. Candidates must have passed 10+2 or equivalent examination with at least 60% marks and 55% for SC or ST candidates in aggregate of three subjects, namely, Physics, Mathematics and any one subject out of Chemistry, Biology, Biotechnology and Technical Vocational subject or minimum 60% (55% for SC/ST candidates) marks in a Diploma recognized by AICTE or a state board of technical education of at least 3-year duration.
2. Candidates must have appeared JEE Mains, 2019.

Yes, you are also eligible for Jaypee Institute of Information Technology University as the basic eligibility criteria of the university says:

The admissions will be both entrance and merit based. For the entrance based admissions, candidates will have to appear JEE Mains. The candidates who score 60% marks in the qualifying exam are eligible to apply for the admission.

Hope this helps!

As your son has a decent percentage there are chances of getting admission in DU but it will also depend on the course which he wants to persue. And if we talk about private colleges like Thapar and Jaypee ,  your son can get admission there very easily. But due to tough competition in DU has a rare chance to dont getting admission. But you can try in DU as well.

ALL THE BEST

Dear Sartak ,

I hope you are doing well !

Mostly every college having own criteria with cut-off marks will vary as per college .If we going through LMNIT then it will between 1450-150 minimum marks required but is based on the last year cut-off. but if we go trough every college then it will not constant .

I hope it will helpful

Thanks

Hello,

As per the official website of the Institute. The Institute is no. 1 in NCR, 3rd in the northern region and at 60th place in the ranking of private and Government Institutes of the country as per its NIRF Ranking. Below is the link for the same:

http://www.jiit.ac.in/jiit-ranked-60th-national-institutional-ranking-framework-nirf-0

hi,

see the cutoff score changes year to year and it depends on various factors like number of participants, questions difficulty level, seat matrix etc. the basic eligibility criteria is . at this score you have decent chances for jappee cse department. The candidate must  have a pass in the 10+2 or its equivalent exam  with Physics and Mathematics as compulsory subjects and either of the mentioned subjects,  Chemistry,  Biology,  Biotechnology,  and Computer Science as optional subjects with 60% marks in 10+2 course.

HELLO YADVENDRA
Since the official cutoffs from the colleges are yet to be decided so let me give you an insight of previous year data
Branch name Closing Rank
4-Year B.E./B.Tech. Course
Biotechnology 660730
Computer Science and Engineering 51072
Electronics and Communication Engineering 96233
Information Technology 54986
5-Year Integrated M.Tech. Course
Computer Science and Engineering 90480
Electronics and Communication Engineering 170406

HOPE IT HELPS!!

Hello,

Counselling and admission is done as per the provisions. If the college accepts it then he may join as non-sponsored. You better visit the campus and talk to the admission section of the college regarding it.

College will inform you if they have this kind of any facility to provide and guide you how to go through the process.

Hope it helps!