Saveetha Engineering College, Chennai All Questions

Of course cse in vit vellore is one of the best in the country

Hello Aspirant


Cyber Security is a specialized course in IT(Information Technology) which is regarded to as a subject relates to computers. So, like all the other computer course you will need to have a strong mathematics background, analytical and statistical skills are required.

Eligibility for the course is: the candidate must have passed class 12th with subjects like mathematics, physics and chemistry.


Good Luck

Let me put some data in front of you about these two colleges.

Comparative Insights                         VIT Vellore          JIIT Noida

Average CSE Package (2019-20)           9.1 LPA                    7 LPA

Course Fees                                            7.80 Lakhs             8.90 Lakhs

Campus Size                                           372 acres              16 acres

NIRF Ranking(2020)                               15                            115

Students overall rating                        4.3/5                        3.8/5

(Info Source: Careers360)

Now as you can see VIT Vellore CSE has an edge over Jaypee institute of information technology, Noida sec 128, but if you are very concerned about location then you might look for JIIT, Noida.

All the very best.

Hi,
As all the colleges are good. But the placement and the fee structure matters during the web options.
I suggest you make the below order for better college
1.COMEDK
2.VITS
3.GGSIPU
4.JIIT
I think the fee structure of COMEDK would be more but the placement is guaranteed.VITS too have placements but the average percentile matters.
All the best!

Dear aspirant, you can easily get CSE in JIIT Noida, Sector 128 branch. It is difficult to get IT with 86-88 percentage.

College administration never told how many seats are under board admission or JEE admission but maximum seats are filled in Noida campus(both 62 and 128) with JEE mains score.

Hello goursiddhant

I hope you are doing good. I would like to know you that

accelaration is actually changing of velocity per sec

intitalc velocity =0 m/s (as start from rest)

final velocity=75m/s

change in velocity=75-0=75m/s

hence required acceleration will be

=75/15=5 m/(s^2)

If you have any other doubt then you can always reach us to clear them :)

Hello,

If you get seat in the second counselling then the seat you got in the first counselling will get cancelled not the seat you got in second counselling. If you did not get seat in the second counselling then you will have the seat that you got in the first counselling only if you have submitted the joining report and all the original documents in the college that you have got in the first counselling that is if you have reported your self in the college that you got in the first counselling. If you do not report then even if you did not get college in the second counselling you will still loose that college that you got in the first counselling.

Hello aspirant,

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Hope, this helps you.

Hello there,

Let we take angle Thita as 'x' . We have to prove that Sinx - Cosx +1 / Sinx + Cosx - 1 = 1/ Secx - Tanx

So now we will take the LHS of the question.

Now multiply the numerator and denominator by Sinx + Cosx +1

Now, our left side becames 1+ Sinx / Cosx

Now again multiply the numerator and denominator by 1- Sinx

So we get , Cosx / 1 - Sinx.

Now just divide the numerator and denominator by Cosx .

Hence We get 1/ Secx - Tanx

Hope it helps you.

Hello aspirant!

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