Saveetha Engineering College, Chennai All Questions

Hello,

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Hello,

We know that, as per the Equation of Motion,

s = ut + 0.5 a t^2

So, for first 3 sec.,

10 = 3u + 0.5 x a x 9

So, 3u + 4.5a = 10.............. ( 1 )

Now, for next 4 sec.,

25 = 7u + 0.5

Hello,

Given that the distance is directly proportional to the square of time.

So, d ∝ t^2

So, d = k.t^2

Where, k is the constant of proportionality.

Now from first condition,

d = 78m and t = 7 sec.

So, 78 = k. 7^2

So, k = 1.59 =

Using s = ut + 1/2a(t^2),  we can write

100 = 4u  + 8a

=> u + 2a = 25             ------(1)

Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write

240 =

Hello Aspirant,

Based on this score chances seem less to get a seat in Government colleges under All India quota seats & state quota seats, You can get a seat in private colleges for MBBS programme. Since it is very late to answer your query, I hope you have checked

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