Saveetha Engineering College, Chennai All Questions

Hello,

First get your concepts clear, you can start off with Grammar, learn all the important topics such as Subject-Verb Agreement, Preposition, Noun, Pronoun, Adjective, Adverb, Active & Passive Voice, Narration etc. You can go through Wren and Martin for this, Having a strong foundation on grammmar will enable you to solve sentence reaarangement, fill in the blanks, error detection etc,

You can work on your vocabulary by reading any newspaper or going through Word Power Made Easy, it's a wonderful book for vocabulary.

Once you have gone through aforementioned steps, then try solving any English Book, you can choose between Plinth to Paramount or SP Bakshi. Along with this, go through previous year papers, anaylse on a regular basis.

Hello,

We know that, as per the Equation of Motion,

s = ut + 0.5 a t^2

So, for first 3 sec.,

10 = 3u + 0.5 x a x 9

So, 3u + 4.5a = 10.............. ( 1 )

Now, for next 4 sec.,

25 = 7u + 0.5 x a x 49

So, 7u + 24.5a = 25............ ( 2 )

Solving ( 1 ) and ( 2 ), we get,

a = 0.12 m/s^2 and u = 3.15 m/s

Now, also as per the Equation of motion,

v = u + at

So, For 8 sec.,

v = ( 3.15 ) + ( 0.12 x 8 )

So, v = 4.11 m/s

Hence, The velocity of object at the end of 8 seconds will be 4.11 m/s

Best Wishes.

Hello,

Given that the distance is directly proportional to the square of time.

So, d ∝ t^2

So, d = k.t^2

Where, k is the constant of proportionality.

Now from first condition,

d = 78m and t = 7 sec.

So, 78 = k. 7^2

So, k = 1.59 = 1.6

Now, d = k. t^2

So, for first four seconds, t = 4sec

So, d = k. 4^2

So, d = 1.6 x 16

So, d = 25.6 m

So, The stone will fall a total distance of 25.6 m in 1st 4 seconds.

Best Wishes.

Using s = ut + 1/2a(t^2),  we can write

100 = 4u  + 8a

=> u + 2a = 25             ------(1)

Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write

240 = 8u + 32a

=> u +4a = 30              ------(2)

Solving Eq.1 and 2 we can say,

a = 5/2 m/s/s and u = 20 m/s

Hence the velocity at t=6 sec, is 20 + 5/2*6 = 35m/s.

Hello Aspirant,

Based on this score chances seem less to get a seat in Government colleges under All India quota seats & state quota seats, You can get a seat in private colleges for MBBS programme. Since it is very late to answer your query, I hope you have checked the seat allotment of All India Quota & West Bengal state counselling & also allotted the seat in any of the medical college.

Do let us know if you have any other query.

Good Luck!

Ranked No. 3 - Silicon India ranked SSE 3rd among the Top 10 Emerging Indian Engineering Colleges.

NIRF 43rd rank

Based on the cut-off marks obtained in the higher secondary (10+2) examination or should have passed the higher secondary examination of Vocational stream as prescribed by the Government.

Cutoff for CSE:

BC - 171.5

BCM - 161.25

MBC - 164.25

OC - 177

SC - 122

SCA - -NIL-

ST - -NIL-