NIT Patna All Questions

Hey there

Marks varies each year as level of questions and number of students vary each year. The rank required for admissions into nits in cse are

1. National Institute of Technology Nagaland, cutoff 26535

2. National Institute of Technology, Mizoram, 26401

3. National Institute of Technology, Manipur, 26160

All

Hi

Jee mains 2019 qualifying cut off is provided below for different categories :-

• General category :- 89.7548849 percentile

• GEN-EWS -78.2174869

• Other Backward Classes (OBC-NCL) -74.3166557

• Scheduled Caste (SC) -54.0128155

• Scheduled Tribe (ST) -44.3345172

• PwD -0.11371730

I hope that you find this helpful

Thank you

hi,

see you did not mention your percentile or score anything, which can not help us to give you any predictable college, however you may use jee  main college predictor to know about you predictable college,

https://engineering.careers360.com/jee-main-college-predictor

see nit jamshedpur and nit pattna both of the nits is excellent in

Hi Naman,

NIT Patna, ranked 134 by NIRF. It has very good placement records. The minimum package is 3 LPA while the average package is above 6LPA and the maximum package is 16.85L per annum in CSE. Companies like Wipro, Google, Infosys, Accenture, Microsoft prefer this college for placements.

Refer

Here I have given you a link. By comparing your gate marks for with cutoff of 2018, you can get idea about the chances of admission. You have to fill application form again even if you miss marks from cutoff by 2-3. There is still chance to get admission.

https://engineering.careers360.com/articles/gate-cutoff

Hello Aspirant, If you got 88.91 percentile in JEE Main then your rank after JEE Main April will be around 1.3 lakhs,Now last year closing Cutoff rank for NIT Patna for SC Home state candidate


Civil Engineering 131159

Computer Science and Engineering 89441

Electrical Engineering 147345

Electronics and Communication Engineering

Hello,

Any percentile around 98  is decent and have probability of getting good branches in NIT Patna. If you score around 98 percentile then your rank will be around 18000-19000 and you will have chances of getting all top branches in NIT Patna. You can get Branches like Computer Science

Hi Ayush,

It is not possible to calculate the exact rank from given percentile so there is a formula for calculating near about rank which is given as below

(100 - your percentile) *869010/100

According to this formula your rank would be around 15,700. According to the last year's trend

Hello Aspirant.

As you've mentioned that you've scored 74.02 in JEE Main examination 2020. Then your chances of getting into NIT Patna are quite difficult but still if you're able to get into NIT Patna then you might face a problem of not getting the demanded branch( If it's CS

Hello,

Your expected rank will be around 22759.You can calculate your expected rank using the formula (100-your total percentile)*869010/100

where 869010 is the total number of candidates appeared in January session.In April session 1200000 candidates are expected to appear then you can calculate your expected rank using the formula (100-your