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hi,

see cutoff score changes year to year and it depends on various factors like number of participants, questions difficulty level, students category, seat reservation etc. nits has 50 percentage seats are reserve for domicile candidates, now coming to jee main april session, its is expected that the number of participants will increase compare to jee main january session, since the nits you have mentioned is one of the top nits, you need to get 250+ score in jee main exam to get btech admission in these nits.

Hello,
Your expected rank will be around 1205.You can calculate your expected rank using the formula given below
(100-your total percentile)*112679/100
112679 is the total number of candidates appeared for JEE main paper 2 in January session.
By Calculation it is (100-98.93)*112679/100=1205

Considering 2019 cut off a candidate with rank 1668 belonging to General category and holding a domicile of Kerala secured a seat in NIT, Calicut and a candidate with rank 2468 belonging to general category and holding a domicile of Kerala seacured a seat in NIT, Tiruchirapalli.
A candidate with rank 1362 belonging to general category from other state secured a seat in NIT, Calicut and a candidate with rank 1075 belonging to General category from other state secured a seat in NIT, Tiruchirapalli.

So, you may have chances of getting a seat in NIT, Calicut and NIT, Trichy if you hold domicile of Kerala.However, cut off is subjected to change it may increase or decrease slightly.

You can also predict the colleges which you may get using our college predictor
https://engineering.careers360.com/jee-main-college-predictor

Hello!!
To calculate your JEE main paper 2 rank,you can use the formula (100-percentile scored)*1384.10
So your rank is approximately 6960.The previous year closing rank for Home state and other state quota for NIT trichy for open category 2468 and 1075 respectively. So it will difficult to get an admission.But the official admission cutoff is not out as of now.Lets hope for the best and prepare well for your April session exam.

Hello Rasmi,

Doctor of Literature [D.Litt.] happens to be a 2-year full-time Doctorate course in Literature. The minimum eligibility for D.Litt is a PhD in Literature with 50% of marks from a recognized board. Most of the colleges and universities offer Doctor of Literature courses, be it a government, private or deemed colleges.  Every institution has their own eligibility criteria, admission process, fees structure, and course pedalogy.

Some of the best universities offering this course in India are:

Indira Kala Sangeet Vishwavidyalaya

Ranchi University

Banaras Hindu University

Rabindra Bharat University

MATS School of Management Studies and Research

Hope this helps you. Careers360 wishes you the best for your future endeavours!

Regards

Hi Shivranjani,

The rank you required for NIT Trichy is depends upon your category like :-

for OBC it should be under 500 for SC it should be under 300 for ST also the rank should be under 300.

The above mentioned ranks are in their category rank.

In general the closing rank for NIT Trichy is around 870.

Hope this will help,please feel free to ask if you have any further queries.

Hi aspirant,
It is difficult to tell you about that but,
you can check your score by the formula,

100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) x 112679/100.

Also you can use the college predictor,

https://engineering.careers360.com/jee-main-architecture-college-predictor

Hope it helps.

Hi! hope you are doing great! NIT trichy is one of the top colleges in colleges of NIT’s and so the cut offs are also high! the cut offs may vary according different criteria and as you haven’t mention that i am attaching one link you may use the link below to know the minimum percentile required

https://www.google.co.in/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy/amp

all the best

Hello!

To predict if you can get into your desired college, first calculate your rank!

To calculate the rank for B.Arch:

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

To check about the colleges:

Refer to the previous year cutoff after calculating the rank from the formula mentioned above.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b- planning/amp

Use our college predictor tool too:

https://engineering.careers360.com/jee-main-architecture-college-predictor

There are 2 types of cut offs namely qualifying cut off and admission cut off. Those Candidates who meet the qualifying cut off are eligible to appear for JEE Advanced. The admission cut off is the minimum score required to have higher chances at that particular institute. Now cut offs change every year depending on various factors such as Total no.of seats available. difficulty of the exam, previous years trends, no.of candidates appearing for the exam and no.of Candidates applying for a course. Cut offs decrease when the availability of seats is more than the Candidates applying. But there has been a steady increase of candidates applying for NIT Trichy than the seats available and hence the rise in the cut offs.

Hello vadivelu,
Ad you have secured 84.3 percentile in the jee main paper 2 it is good.
To calculate the rank for B.Arch:
100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.
So rank formula is (100 - your total score) X 112679 /100
Your estimated rank will be 17690 crl rank . And your category rank will be differ from this.
The cut off for nit trichy for b.arch for SC category is 117 to 273 . It will be difficult you to secure seat in nit trichy.
Try to score above 97+ percentile to grab a seat in next attempt
All the best
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