T1 = 27 = 300K

Let initial pressure be P1 and final be P2 .

Now, as gas is compressed to 10 times the original pressure then :-

P1/P2 = 1/10

And, gamma = 1.4

And since the gas is compressed, so we will use

(T1 / T2 )^gamma =

Dear student,

T1 = 10 = 283K

Let initial volume be V1 and final be V2 .

Now, as gas is adiabatically compressed to one third of it's original volume then :

V2 = 1/3 of V1

That is :-

V2 / V1 = 1/3

And, gamma = 1.5

And

Hello there!

Here is the solution regarding your question.

Given,

T = 27°C [which is equal to 300 K].

Work done = 2.303 RT log Vf / Vi  [ for isothermal process ].

W = 2.303 x 8.31 x 300 x log 3/1 [ log 3 = 0.48 ].

W

Hello there!

Here is the solution regarding your question.

Given,

T = 127°C  [which is equal to 400 K].

Pi = 1 x 10 dyne / cm²

Pf = 5 x 10 dyne / cm²

Since, the process is Isothermal. Thus,

PiVi = PfVf

Vf = PiVi / Pf

Vf

Hello there!

Here is the solution regarding your question.

Given,

Vi = 1.2 litres

T = 37°C  [ and that is equal to 310 K ].

Pi = 10 dyne / cm²

Vf = 3 x Vi

The process mentioned in the question is Isothermal. So,

PV = constant

PiVi=

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