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Staff Selection Commission Multi Tasking Staff Exam

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Question : The element with highest first ionisation energy is:

Option 1: Hydrogen

Option 2: Helium

Option 3: Lithium

Option 4: Sodium

Team Careers360 26th Jan, 2024

Correct Answer: Helium


Solution : The correct option is Helium.

Ionisation energy is the energy required to remove an electron from a neutral atom, forming a positively charged ion. Helium has the highest ionisation energy because it has the smallest atomic size among all the elements and a full electron

12 Views

Question : At what rate percent per annum will a sum of money triples in 20 years on simple interest?

Option 1: 10%

Option 2: 12%

Option 3: 18%

Option 4: 20%

Team Careers360 26th Jan, 2024

Correct Answer: 10%


Solution : Let $P$ be the principal sum.
Total amount = $3P$
Simple interest = $3P- P$ = $2P$
Term, $n$ = 20 years
Let $R$ be the rate of interest.
Simple interest, SI = $\frac{PnR}{100}$
⇒ $2P = \frac{P×20×R}{100}$
⇒ $R= \frac{200}{20}= 10$%
Hence, the correct

62 Views

Question : Directions: In a certain code language, HEG is coded as 840, and JFD is coded as 720. What is the code for JDK in that code language?

Option 1: 1380

Option 2: 1320

Option 3: 1280

Option 4: 1400

Team Careers360 27th Jan, 2024

Correct Answer: 1320


Solution : Given:
HEG is coded as 840, JFD is coded as 720.

Multiply the positional values of the letters of HEG, and then the resultant is multiplied by 3, to obtain the required code –
H→8; E→5; G→7
(8 × 5 × 7) × 3 =

12 Views

Question : Successive discounts of 33% and 30% are equivalent to what single discount?

Option 1: 60.4%

Option 2: 50.5%

Option 3: 45.9%

Option 4: 53.1%

Team Careers360 26th Jan, 2024

Correct Answer: 53.1%


Solution : Single equivalent discount = $(a+b-\frac{a×b}{100}$)%, where $a$% and $b$% are successive discounts.
Here $a$ = 33% and $b$ = 30%
So, Single equivalent discount $= 33+30 - \frac{33×30 }{ 100}=63-9.9 = 53.1$%
Hence, the correct answer is 53.1%.

27 Views

Question : A man bought an old printer for Rs. 2200 and spent Rs. 800 on its repair. He sold it for Rs. 3600. Find his profit percentage.

Option 1: 30%

Option 2: 20%

Option 3: 15%

Option 4: 25%

Team Careers360 27th Jan, 2024

Correct Answer: 20%


Solution : Given: A man bought an old printer for Rs. 2200 and spent Rs. 800 on its repair. He sold it for Rs. 3600.
The total cost of the printer (CP) = (2200 + 800) = Rs. 3000
The selling price (SP) = Rs. 3600
Profit

20 Views

Question : Directions: In the following question, select the missing number of the given series.
108, 129, 104, ?, 100, 137, 96

Option 1: 138

Option 2: 135

Option 3: 133

Option 4: 140

Team Careers360 26th Jan, 2024

Correct Answer: 133


Solution : Given:
108, 129, 104, ?, 100, 137, 96

Add and subtract alternatively starting with 21 in each number with a difference of 4, to get the required missing number –
108 + 21 = 129; 129 – 25 = 104; 104 + 29 = 133;

16 Views

Question : The simple interest on a certain sum of money for 2 years at 7% per annum is double the compound interest on INR 1,000 for 2 years at 10% per annum, compounded annually. What is the sum placed on simple interest?

Option 1: INR 1,000

Option 2: INR 2,000

Option 3: INR 3,000

Option 4: INR 4,000

Team Careers360 26th Jan, 2024

Correct Answer: INR 3,000


Solution : Simple interest on a certain sum of money for 2 years at 7% per annum = 2 × compound interest on INR 1,000 for 2 years at 10% per annum
According to the question,
$\frac{P_1nR}{100}= 2 × [P_2(1+\frac{R}{100})^n - P_2]$
Here $P_1$ is the

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