Question : A circular wire of length 168 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 5 : 7. What is the length (in cm) of the diagonal of the rectangle?
Option 1: $\sqrt{4127}$
Option 2: $\sqrt{3137}$
Option 3: $\sqrt{1813}$
Option 4: $\sqrt{3626}$
Correct Answer: $\sqrt{3626}$
Solution :
The length of the wire is equal to the perimeter of the rectangle.
The sides of the rectangle are in the ratio 5 : 7.
Let the sides be $5x$ cm and $7x$ cm.
The perimeter of the rectangle $=2(5x + 7x) = 24x$ cm
Given that the perimeter is 168 cm,
So, $24x = 168$
⇒ $x = \frac{168}{24} = 7$ cm
The sides of the rectangle are $5x = 35$ cm and $7x = 49$ cm
The length of the diagonal of a rectangle $=\sqrt{(\text{side}_1)^2 + (\text{side}_2)^2}$
$=\sqrt{35^2+ 49^2}$
$= \sqrt{1225 + 2401}$
$=\sqrt{3626}$ cm
Hence, the correct answer is $\sqrt{3626}$.
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