Question : If a number x is divisible by 8, 12 and 16, and it leaves the remainder of 3 in each case, the possible value of x is:
Option 1: 148
Option 2: 149
Option 3: 150
Option 4: 147
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Correct Answer: 147
Solution :
Given: A number x is divisible by 8, 12, and 16.
It leaves a remainder of 3 in each case.
Taking the LCM of 8, 12 and 16 = ( 2×2×2×3×2) = 48
So, the number x = 48k + 3 (let k be any integer)
put k = 3 and then,
⇒ x = (48 × 3) + 3 = 147
Hence, the correct answer is 147.
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