Question : If $\sqrt3=1.732$, then the value of $\frac{9+2\sqrt3}{\sqrt3}$ is:
Option 1: 7.169
Option 2: 7.196
Option 3: 5.198
Option 4: 7.296
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Correct Answer: 7.196
Solution :
Given: $\sqrt{3} = 1.732$
$\frac{9+2\sqrt{3}}{\sqrt{3}}$
To eliminate the root from the denominator, multiply and divide by $\sqrt{3}$
= $\frac{9+2\sqrt{3}}{\sqrt{3}}$ × $\frac{\sqrt{3}}{\sqrt{3}}$
= ${\sqrt{3}×9+\sqrt{3}×2\sqrt{3}}$
= $\frac{\sqrt{3}×9+6}{3}$
= $\frac{3(3\sqrt{3}+2)}{3}$
= $3\sqrt{3}+2$
= $3×1.732+2$
= $7.196$
Hence the correct answer is 7.196.
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