Question : The value of $(\sin^445°+ \cos^460°) + (\tan^445°+ \cot^445°)$ is:
Option 1: $\frac{37}{16}$
Option 2: $\frac{33}{16}$
Option 3: $\frac{35}{16}$
Option 4: $\frac{39}{16}$
Correct Answer: $\frac{37}{16}$
Solution :
Given: $(\sin^445°+ \cos^460°) + (\tan^445°+ \cot^445°)$
= $(\frac{1}{\sqrt2})^4 + (\frac{1}{2})^4 + (1)^4 + (1)^4$
= $\frac{1}{4} + \frac{1}{16} + 1 + 1$
= $\frac{4+1+16+16}{16}$
= $\frac{37}{16}$
Hence, the correct answer is $\frac{37}{16}$.
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