NIT Trichy All Questions

Hello Aspirant,

The exact prediction would be difficult regarding your admission possibilities based on your percentile. But with this percentile you should have the chance to get National Institute of Technology Tiruchirappalli- B.tech Computer Science, ECE, EEE, Mechanical Etc.

To check your other admission possibilities, You can use JEE Main

Hello Aspirant,

The exact prediction would be difficult regarding your admission possibilities based on your percentile. But with this percentile you should have the chance to get National Institute of Technology Tiruchirappalli- B.tech Computer Science, ECE, EEE, Mechanical Etc.

To check your other admission possibilities, You can use JEE Main

Your rank should be around 7000 which is a very good rank but to be honest it won't be enough to get Computer Science Branch in NIT Trichy , NIT Warangal or NIT Surathkal . You need to work harder to get CSE in any of these colleges .

But

Hi KedarNath,

If you have secured 97.6 percentile in JEE Main paper, you rank would be approximately in between 29000 to 34000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score.

Also, you can

Hello

It would be difficult to tell you exactly about the marks required for admission as the cutoff varies ever year depending on many factors. Some of the determining factors are

Number of seats available
Number of candidates appeared in the exam
Previous years’ cutoff trends
Difficulty level of the

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 230982 . Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100. With this rank

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 156682. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100. You haven't mentioned the