A perfect square number can never have the following digit In its ones place
Hello,
A perfect square number can never have 2, 3, 7, or 8 in the ones place. When any integer is squared, the unit digit of the result can only be 0, 1, 4, 5, 6, or 9. Therefore, digits 2, 3, 7, and 8 never appear at the ones place of a perfect square.
For example:
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
From these examples, we can see that the unit digits repeat only among 0, 1, 4, 5, 6, and 9, so a perfect square will never end in 2, 3, 7, or 8.
Helpful Careers360 resources for students:
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Squares and Square Roots – Concept and Examples:
https://school.careers360.com/articles/squares-and-square-roots
Maths Study Material and Sample Papers:
https://school.careers360.com/download/ebooks-and-sample-papers
Careers360 School Mathematics Preparation Resources:
https://school.careers360.com/articles
Thank you.
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