MNNIT Allahabad All Questions

hi,

see most of the mncs in india accept 2 years academic  gape between studies, so as per the eligibility criteria, if you have good score and well programming concepts you will not faced any issue regarding placement. and some of the top tier 1 startup companies search talents and

hi,

see cutoff score changes year to year and it depends on various factors like number of participants, seat matrix, question difficulty level etc. now jee main april session exam is yet to held, if the number of candidates increased this time it will have effect on your over all

Hi Akash.

Predicting you admission into  good college like MNNIT just by your marks is difficult as the cutoff scores haven't been announced yet and will be announced after April's JEE Mains. If you provide your percentile, it will be easier to predict.

Still, with 150 marks in January's JEE

Hello Aspirant.

Yes , You have a chance to get admitted into Motilal Nehru National institute of technology Allahabad.

But there are many factors behind the first factor is of you being an SC candidate and your home state quota also plays a major role in you getting this college.

Hello aspirant,

Based on your score in JEE MAINS exam your rank will be around 37,000. According, to your rank , caste category I will list out the top colleges you can get along with the branch-

• IIIT Delhi - Indraprastha Institute of Information Technology ( CSE )
• DTU -

Hello Aspirant .

The answer to your question is YES, you can get admission in MNIT Allahabad with this much percentile as you belong to OBC category and also due to a factor of homestate.

Coming on to the branch, you can get any of your desired branch in MNIT

As you got 97.86 percentile in Jee Main January Session 2020, you expected rank would be (100-percentile score) * (869010/100). If the no. Of candidates in April Session increases to 12,00,000 then your expected rank would be - (100- percentile score) * (1200000/100) i.e. almost 25,680. This would be your

Hello,
Your expected rank will be around 18522.You can calculate your expected rank using the formula given below
(100-your total percentile)*869010/100
869010 is the total number of candidates appeared in January session.
In April session it is expected that 1200000 candidates will appear so your expected rank can calculated using

You can calculate your rank in JEE Main Paper 1 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 1 (Jan) are around 869000, your rank will be around 5000. However as the no. of students in April changes,

Agrim, you may not get admission in MNIT with this score. You haven't mentioned whether this score is of paper 1 or 2, but anyway, your Percentile is not enough.

For paper 1, your rank will be around 79,514. You can calculate it using the formula:
(100- your percentile)869010/100.

Here