NIT Calicut All Questions

Hi dear,

You have scored 88.82 percentile in JEE main paper 2 that means your rank should be around 12597. This is not your final rank.Your final rank will depend on number of student appear in April month exam. You can also calculate your rank as

Rank=(100-your percentile)×112679÷100

With this rank you have low chance to get NIT CALICUT. You can check cutoff of all college here

https://www.google.co.in/url?q=https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning&sa=U&ved=2ahUKEwjI3Nqsk6TnAhXUYisKHdLTD88QFjAAegQICRAB&usg=AOvVaw3NUYS-M5KQ_IMws3rLkS0e

Hope it helps

Hello ashish ,
As you have secured 99.5 percentile in the jee mains  paper it is very good .
To calculate the rank for B.Arch:
100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.
So rank formula is (100 - your total score) X 112679 /100 .
Your estimated rank will be 563 crl rank .
Your satisfying the cut off of the NIT calicut in b.arch
You can easily grab a seat in b.arch of NIT calicut
All the best

Hello,
Your expected rank will be around 1205.You can calculate your expected rank using the formula given below
(100-your total percentile)*112679/100
112679 is the total number of candidates appeared for JEE main paper 2 in January session.
By Calculation it is (100-98.93)*112679/100=1205

Considering 2019 cut off a candidate with rank 1668 belonging to General category and holding a domicile of Kerala secured a seat in NIT, Calicut and a candidate with rank 2468 belonging to general category and holding a domicile of Kerala seacured a seat in NIT, Tiruchirapalli.
A candidate with rank 1362 belonging to general category from other state secured a seat in NIT, Calicut and a candidate with rank 1075 belonging to General category from other state secured a seat in NIT, Tiruchirapalli.

So, you may have chances of getting a seat in NIT, Calicut and NIT, Trichy if you hold domicile of Kerala.However, cut off is subjected to change it may increase or decrease slightly.

You can also predict the colleges which you may get using our college predictor
https://engineering.careers360.com/jee-main-college-predictor

Hello!!

To calculate your JEE main rank,you can use this formula ((100-your total percentile)*869010/100).This formula will give your general category rank(Common list rank).And your rank is approximately 39105

Since you are a not domicile of Kerala,you cannot avail the home state quota of NIT Calicut.You will come under the other state quota.The previous year's cutoff of NIT Calicut for different b.tech branches and categories is given in the below given website.

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut/amp

To know about all the possibilities of your admission into various colleges,visit the below given website.You will have to enter the details asked such as your percentile,category,home state etc..and the possibilities will be predicted.

https://engineering.careers360.com/jee-main-college-predictor

Hey there hope you're doing well.
Dear aspirant, congratulation on scoring a good percentile in the JEE MAIN examination paper 2 B ARCH. As you say your percentile is 97 you can calculate your rank by the formula

(100 - your percentile score) 112679/100
Also I m providing you with our college predictor link .Go through this to get a better idea.
Link- https://engineering.careers360.com/jee-main-architecture-college-predictor.
Thank you hope this helps you!

Hello!

Congratulations! With such a high percentile, I believe that you can get into NIT, Calicut!

To predict if you can get into your desired college, first calculate your rank!

To calculate the rank for B.Arch:

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

To check about the colleges:

Refer to the previous year cutoff after calculating the rank from the formula mentioned above.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b- planning/amp

Use our college predictor tool too:

https://engineering.careers360.com/jee-main-architecture-college-predictor

Hello Sourabh

Link: https://engineering.careers360.com/articles/jee-main-cutoff-for-manit-bhopal

Maulana Azad Institute of Technology, Bhopal offers 7 B.Tech courses for the students namely Chemical Engineering, Civil Engineering, Computer Science and Engineering, Electrical Engineering, Electronics and Communication Engineering, Mechanical Engineering and Materials Science and Metallurgical Engineering. The institute has a total of 817 seats for these engineering programmes.

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 82903. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.

With this rank, it might be difficult for NIT of your Home State even with OBC reservation. You might be able to get a good college through JOSAA. But if you want to appear for JEE Advanced, you qualify based on your percentile because the expected qualifying percentile is 85 and above. But if you want to study in NIT, you may have to appear in April session.

For previous years cut offs of NIT Calicut, please visit our page: https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut

Now to predict colleges, please use our college predictor:https://engineering.careers360.com/jee-main-college-predictor

Hey aspirant!

It is difficult to predict the exact ranks currently as the April Jee mains session has yet to take place. However, you can predict your expected rank by this formula:-

(100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

In your case the rank comes out to be around 191182. I am sorry but at that rank, getting NIT Calicut would be very very difficult (honestly no chance based on previous years trends). As you can see the previous year's cutoff scores for Nit Calicut in this link https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits/amp

to understand that your chances are next to zero for Nit Calicut.

However, you still have a good chance to redeem yourself in the April attempt and hence work hard for it.

Also, you can use this college predictor to know what best colleges you would get based on these January scores

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor

Hello

It would be difficult to calculate the state rank. According to your percentile, you have good chances to get a seat in NIT Calicut in ECE, EEE, Mechanical engineering. Use the JEE Main College Predictor tool to check your college admission chances on the basis of your percentile score, category, home state

https://engineering.careers360.com/jee-main-college-predictor

Good Luck!