IIIT Pune All Questions

Hello Ramesh ,

• Indian institute of information technology , Pune is good . It was established in 2016 year.
• Its offering B.tech , M.tech and Ph.D .
• Acceptable exams are GATE for admission .
• Placements also good (According to students rating in the given article).
• Facilities also good .
• Its also have clubs like Coding club , Robotics club , Sports club , innovation cell e.t.c.

For more information and updates regarding the college i am providing small article here please go through it once.

https://www.careers360.com/university/indian-institute-of-information-technology-pune

I hope you got it !!!

All the best !!!

IIIT PUNE was ranked 15th position among the 'TOP ENGINEERING COLLEGES OF INDIA' in 2019. Talking about the college it is quite good and CSE is also a great choice in this college to pursue.

Hi aspirant,

You belong to OBC category and have obtained 59,000 OBC category rank. With such a high rank it would be very tough for you to get admission in NIT. You might get some lower IIITs. Better you can apply in state counselling for getting admission in state government engineering colleges in states like Haryana, Bihar, Madhya Pradesh, Rajasthan, Uttar Pradesh et cetra. You can predict your college and branch based on this rank by using our college predictor tool by clicking on the following link: https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hope it helps you.

Hello there, you should you with IIIT Pune. There are many reasons. First in India government college tab is important believe it or not so IIIT tag will surely help you in many fields whether in placement or higher studies. (It's a bitter truth but this tag is important and VIT doesn't have this tag).

Second, fees- IIIT Pune fees is much less than that of VIT.

Third overcrowding in VIT they have more than 500 students in the same branch. But this is not the case with IIIT

But it totally depends on you that which college you want.

Good luck!!

Hello!!

Hope you are doing great!!!

Your All India Rank would be around 60917 approximately,Calculated by using the formula 100-92.99*869010/100 where 92.99 is your mains percentile and 869010 is the number of candidates appeared in January session.As per the previous year cutoff trends,With this rank you can not get seat in IIT Pune.The previous year cutoss for Computer Science for OBC Category is around 9799 AIR.You may have to appear for july session.You can check the previous year cutoff for IIIT Pune in the link provided below:

https://www.careers360.com/university/indian-institute-of-information-technology-pune/cut-off?

For checking the probabilities of colleges,you can use our college predictor: https://engineering.careers360.com/jee-main-college-predictor

Hope it helps you!!!

Hello,

Your expected rank will be around 60917 and the formula to calculate it is (100-your total percentile)*869010/100

In January session 869010 candidates appeared in JEE Main. Your rank based on category will be in between 16000-18000. It is not mentioned if you belong to OBC-NCL or OBC-CL, if you belong to OBC-CL then you will come under general category.In 2019 the cut off in round 7 for IIIT, Pune for CSE was 9799. This is for OBC-NCL category and for general category it was 23660. Considering this you may get seat whether you belong to OBC-NCL or OBC-CL. However, cut off changes depending on number of candidates appeared, difficulty of exam, number of seats available etc.

You may try our JEE main college predictor to know the colleges you may get https://engineering.careers360.com/jee-main-college-predictor

Hey Mohan

With rank formula ((100-Your percentile)*869010/100), your General rank with 92.99 percentile comes out to be around AIR 61,000. Last year cutoff was:

• IIIT Pune, OBC candidate: 9799 rank for CSE

Analysing your rank to OBC category, sorry but it would be difficult for you to take admission in CSE at IIIT Pune. You may give your best in July attempt and increase your score.

Note: This data is on the basis of previous year record and may change in the upcoming sessions depending upon cutoff and number of candidates appearing. For further doubts, visit; IIIT Pune

Hello student you can calculate and get your rank easily by using this formula

100 -( your total percentile) 869010 /100

In your case your rank must be around - 43,450

Cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination.

As per previous year records its expected that you need to secure rank around 5000 (EWS) I hello student

Last year the cut off for EWS category was 4591

For more updates refer to the link mentioned below - https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-iiit-pune/amp

Feel free to comment if you have any doubt

Good luck