IIIT Bhubaneswar All Questions

JEE Main 2019 is being conducted twice by NTA for the first time and the rank will be based on NTA percentile so the exact prediction would be difficult about the qualify score & admission possibilities.

Based on this score your probable rank will be 380,110 - 420,110. You may

Hello aspirant

Now we can't predict your score because percentile is given according to the highest marks in the exam

Wait for the qualifying cutoff score which is going to release in April .

Write April exam also for better score

Hope helpful to you

All the best

Thank you

JEE Main 2019 is being conducted twice by NTA for the first time and the rank will be based on NTA percentile so exact prediction would be difficult.

Based on this score your probable rank will be 206,791 - 236,791, You may not be eligible for JEE Advance & NIT,

It would be difficult to predict exactly as JEE Main 2019 is conducted twice by NTA first time and the rank will be based on NTA percentile score. 

Based on this score, Your probable rank will be 66,866 - 74,366, The chances seems less to get a seat for the

Hello Anirudh,

  After considering your NTA score your probable rank is around 110530 (can change slightly after the second exam). With this rank you can expect a seat in NITs like NIT srinagar, NIT agartala, etc. For more information about NIT branchwise cutoff you can visit: https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

Hello

Greetings

Your percentile is 85 It means 85% student of the Total student appeared for the Exam are Behind You Therefore 15% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated Approximate rank is 131170

 But Note that This is Not Your

The cutoffs for NITs (National Institute of Technology) and IIITs (Indian Institute of Information Tech) cannot be predicted as the JEE Main Exam is happening twice this year so the cutoffs will be based on the basis of various factors. The rank for percentile 85.4067139 will be around 127620(+-). Note

Hello Rithvik

With 85 percentile score in the JEE Main 2019 exam, your expected rank will be around 131170.

If you belong to General category, chances are tough for admission to decent Engineering Colleges. You may try for admission in Tezpur University, Tezpur,
Guru Ghasidas Vishwavidyalaya, Bilaspur

However, nothing can

Hello Rithvik

JEE Main 2019 exam is being conducted twice a year by NTA for the first time and this time scores will be normalized on the basis of Computer Based exam and two attempts.

It is difficult to tell you the expected cutoff or the minimum percentile required to