Centurion Institute of Technology, Bhubaneswar All Questions

Hello,

TANCET Mtech normalized score 51 is grade A. In your question, you have not mentioned which score it is? if it actual or raw score then please mention normalized score in the comment section. if it is normalized score then your grade will be B. Grade B indicates :-

Hello aspirant,

Below is the cut-off score for BE Mechatronics Engineering in 2018-

Round 1: 2952-5338

Round 2: 2952-15321

Round 3: 2952-15321

Round 4: 2952-15321

Round 5: 2952-15321

Thank you.

Hi Pradhap,

The cut off score for CIT College, Coimabtore is not available but the details regarding rank are are there. The cutoff rank for SC was 17509 and SC-Arunthiyars was 19582.

Hi Aspirant,

According to the given percentile, your rank would be around 2,60,703. This rank is calculated using the given formula

(100-your percentile)*869010/100

So you can easily get Centurion Institute of Technology(CIT), Bhuwaneshwar.

For prediction of more colleges according to your rank and category you can use JEE-Main College Predictor

Yes Coimbatore Institute of Technology is one of the best institutes of Engineering in India. And CSE branch is one of the most upcoming branch as we all know, so it has great placement opp of course from the CIT campus. The teaching faculty and the facilities as well are

Hello Abhishek,

ICT Mumbai, i.e. Institute of Chemical Technology is a UGC approoved, NAAC A++ credited institute located in Mumbai. It is a quite reputed and old institute. The average package is around 3.5 lakhs, where as highest package was around 14 lakhs. There are good companies visiting the campus,