NIT Calicut All Questions

Hello aspirant

As you got 98 percentile in JEE Mains. Also, you have an obc quota so according to the previous cutoffs there are good chances for you to get CS branch in NIT Calicut. As, you have home state quota also, then you can get admission in 2th or

You can't score Your Percentile on the basis of Marks because Percentile depend on a lot of other factors too which are equally important. Because Students are less this time and also Paper Variation also affects a lot. So One can't decide easily the percentile on the basis of marks.

Hello,

The placement record of NIT Calicut for B. Tech. CSE Engineering is very good. Last year, the highest package offered was around INR 40 LPA and the average package offered was around INR 12 LPA.

For NIT Kerala

The highest package offered was around INR 50 LPA and the

Hello
PAIDIKALA YESUKRISHNA , If you want admission in CSE branch of any of the college: NIT WARANGAL, NIT CALICUT, NIT THIRUCHIRAPALLI, NIT SURATHKAL, NIT ROURKELA and IIIT HYDERABAD then you must be give the exam of JEE mains 2020 because all the mention colleges are required cutoff of JEE

Hello Aspirant,

NIT Calicut ranks 23 by NIRF while NIT Surathkal has NIRF rank of 13 which makes it better than NIT Calicut and other NITs.

Talking about faculties, NIT Surathkal has more better faculty where most of them are from thermal backgrounds.

Placements are satisfactory in both the NITs

Hello,

You haven't mentioned whether you belong to OBC-NCL or OBC-CL, if you come under OBC-CL then you are considered as general category. Your overall category rank is expected to be around 6084 and you can calculate it by the formula (100-your total percentile)*112679/100 where 112679 is the total number

Hello,

While it is a bit ambiguous with what you are comparing NIT Surathakal Nanotech. But talking in general, these two colleges are more or less in same level. If a company visits either of the two colleges, it generally visits the other too.

Speaking of general placements, past recruiters

Hi Aysha,

You got 98.4 percentile in JEE main exam, your rank would be approximately in between 1500 to 2000. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680,