IIEST Shibpur All Questions

Computer Science and Information Technology are branches which are highly in demand in the coming future. They've got great placements.

CS has a little just a little edge over IT when companies approach for campus placements, they prefer CS Engineers a bit over IT ones. Still both of these almost

hi,

see as per your score you are eligible to apply in all institute, you have the qualifying marks criteria, however bits admission process is basis on score in bitsat exam, however you are not eligible to give bit sat, since you have passed 12th in 2018. now coming to

HELLO ASPIRANT
since it is very difficult to predict the exact rank but we do have a backup we have a formula to calculate the expected rank that is (100 – Total percentile) x 869010/100.So according to formula your expected rank for present percentile for January session comes out to

hello aspirant..,

you can easily get admission in nit durgapur for the mechanical engineering course with your percentile obtained in jee mains examination easily. According to the expected cutoff for this year for sc category it was about 54.01 . so you can also try for the advanced examination too.

Hello Parthib,

IIEST (Indian Institute of Engineeering Science and Technology), Shibpur takes admission for UG courses through JEE-Mains. Cut-off ranks for CSE of different rounds of previous year are given below :

Round 1

HS* - 9379 and OS* - 10909

Round 2

HS - 9967 and OS - 11441

Hello Prathib,

Hope everything is going fine.

Your question seems to be confusing. You didn't mentioned for what Course or college you are asking about and even whether JEE paper1 or paper 2.

So, kindly ask it again.

Hope you ger it. Feel free to ask.

BEST OF LUCK.

Hello!

It is difficult to tell the exact qualifying percentile for JEE Mains 2020 but according to the projected cutoffs you qualify quite safely for JEE advanced.

Could you specify which college you mean so that I can aid you further?

Hope this helps.

HELLO KSHAMA

Congratulations for your result and qualifying JEE mains.

since it is very difficult to predict the exact rank but we do have a backup> we have a formula to calculate the expected rank that is (100 – Total percentile) x 869010/100.

So according to formula your expected rank