VNIT Nagpur All Questions

• General: 1549-2004 (other state) 897-1792(home state)
• SC: 159-332(OS) , 169-292(HS)
• ST: 100-158(OS), 148-299(HS)
• OBC-NCL: 555-745(OS), 561-966(HS)
• EWS: 334-361(OS), 354-464(HS)

hi,

see if you have passed b.sc course in mathematics/ physics/ chemistry/ computer science and should have mathematics as a subject in your b.sc course you are eligible to apply for btech course from direct second year. there is lateral entry entrance test, which is conducts in state wise, bsc

• Fees- Rs 9, 27,500
• Approvals- UGC, AICTE, NIRF
• NIRF Rank-31
• Academic rating- 8
• Placement rating- 8.7

• Fees- Rs 6, 25,000
• Approvals- UGC, AICTE, NIRF, NBA
• NIRF Rank- 42
• Academic rating- 7.6
• Placement rating-

I don't think that doing masters at this age would be of any benefit. Even after doing your masters you are going to give your 2 years and after that your age will be an actor and you cannot start your career at the age better you can use your

Looks a bit difficult. It will also depend on the branch you need or want to choose. For example branches like computer science and IT look difficult at 96 percentile but yoh may get some branches like mechanical or refining OR metallurgy etc.

So Do apply and let's hope for

HELLO CHIRAG

Congratulations for your result and qualifying JEE mains. you have very high weightage on your side obc cat and home state quota.

Since official cutoffs are yet to be decided so let us analyse your chances based on previous year cutoffs.

• Visvesvaraya National Institute of Technology, Nagpur(VNIT Nagpur)

Hello Shubham

With this percentile in JEE MAINS PAPER 1,your expected rank should be 15,555 and you have mentioned that you belong to general category,so there is less chances for you to get any NITs due to low marks.However,you can wait for the official cut offs of NITs and also

Dear Aspirant

Sorry to disappoint you but ,To get vnit nagpur at this score is too difficult

A formula is given by National Testing Agency to calculate rank in Jee mains .The formula is No of Candidates appeared in session /100*(100- Nta score ).

So the no of candidates apperared